Solve 24x^2-12x-12/3x-3=y

$$\frac{ 24 { x }^{ 2 } -12x-12 }{ 3x-3 } = y$$

Solve for y

$$y=8x+4$$

$$x\neq 1$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3\left(x-1\right).

$$24x^{2}-12x-12=y\times 3\left(x-1\right)$$

Use the distributive property to multiply y\times 3 by x-1.

$$24x^{2}-12x-12=3yx-y\times 3$$

Multiply -1 and 3 to get -3.

$$24x^{2}-12x-12=3yx-3y$$

Swap sides so that all variable terms are on the left hand side.

$$3yx-3y=24x^{2}-12x-12$$

Combine all terms containing y.

$$\left(3x-3\right)y=24x^{2}-12x-12$$

Divide both sides by 3x-3.

$$\frac{\left(3x-3\right)y}{3x-3}=\frac{12\left(x-1\right)\left(2x+1\right)}{3x-3}$$

Dividing by 3x-3 undoes the multiplication by 3x-3.

$$y=\frac{12\left(x-1\right)\left(2x+1\right)}{3x-3}$$

Divide 12\left(-1+x\right)\left(1+2x\right) by 3x-3.

$$y=8x+4$$

Solve for x

$$x=\frac{y-4}{8}$$

$$y\neq 12$$