Solve 24/10*25/100+x*20/100=366

$$\frac{ 24 }{ 10 } \times \frac{ 25 }{ 100 } +x \times \frac{ 20 }{ 100 } =366$$

Solve for x

$$x=1827$$

Steps for Solving Linear Equation

Reduce the fraction \frac{24}{10} to lowest terms by extracting and canceling out 2.

$$\frac{12}{5}\times \frac{25}{100}+x\times \frac{20}{100}=366$$

Reduce the fraction \frac{25}{100} to lowest terms by extracting and canceling out 25.

$$\frac{12}{5}\times \frac{1}{4}+x\times \frac{20}{100}=366$$

Multiply \frac{12}{5} times \frac{1}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{12\times 1}{5\times 4}+x\times \frac{20}{100}=366$$

Do the multiplications in the fraction \frac{12\times 1}{5\times 4}.

$$\frac{12}{20}+x\times \frac{20}{100}=366$$

Reduce the fraction \frac{12}{20} to lowest terms by extracting and canceling out 4.

$$\frac{3}{5}+x\times \frac{20}{100}=366$$

Reduce the fraction \frac{20}{100} to lowest terms by extracting and canceling out 20.

$$\frac{3}{5}+x\times \frac{1}{5}=366$$

Subtract \frac{3}{5} from both sides.

$$x\times \frac{1}{5}=366-\frac{3}{5}$$

Convert 366 to fraction \frac{1830}{5}.

$$x\times \frac{1}{5}=\frac{1830}{5}-\frac{3}{5}$$

Since \frac{1830}{5} and \frac{3}{5} have the same denominator, subtract them by subtracting their numerators.

$$x\times \frac{1}{5}=\frac{1830-3}{5}$$

Subtract 3 from 1830 to get 1827.

$$x\times \frac{1}{5}=\frac{1827}{5}$$

Multiply both sides by 5, the reciprocal of \frac{1}{5}.

$$x=\frac{1827}{5}\times 5$$

Cancel out 5 and 5.

$$x=1827$$