Solve 225/1+0.2*0.850.7^2-273

$$\frac{ 225 }{ 1+0.2 \cdot 0.85 { 0.7 }^{ 2 } } -273$$

Evaluate

$$-\frac{235803}{3611}\approx -65.301301579$$

Solution Steps

Multiply 0.2 and 0.85 to get 0.17.

$$\frac{225}{1+0.17\times 0.7^{2}}-273$$

Calculate 0.7 to the power of 2 and get 0.49.

$$\frac{225}{1+0.17\times 0.49}-273$$

Multiply 0.17 and 0.49 to get 0.0833.

$$\frac{225}{1+0.0833}-273$$

Add 1 and 0.0833 to get 1.0833.

$$\frac{225}{1.0833}-273$$

Expand \frac{225}{1.0833} by multiplying both numerator and the denominator by 10000.

$$\frac{2250000}{10833}-273$$

Reduce the fraction \frac{2250000}{10833} to lowest terms by extracting and canceling out 3.

$$\frac{750000}{3611}-273$$

Convert 273 to fraction \frac{985803}{3611}.

$$\frac{750000}{3611}-\frac{985803}{3611}$$

Since \frac{750000}{3611} and \frac{985803}{3611} have the same denominator, subtract them by subtracting their numerators.

$$\frac{750000-985803}{3611}$$

Subtract 985803 from 750000 to get -235803.

$$-\frac{235803}{3611}$$

Factor

$$-\frac{235803}{3611} = -65\frac{1088}{3611} = -65.3013015785101$$