Solve 22/752*5left(2*30+53right)

$$\frac{ 22 }{ 7 } 52 \cdot 5 \left( 2 \cdot 30+53 \right)$$

Evaluate

$$\frac{646360}{7}\approx 92337.142857143$$

Solution Steps

Express \frac{22}{7}\times 52 as a single fraction.

$$\frac{22\times 52}{7}\times 5\left(2\times 30+53\right)$$

Multiply 22 and 52 to get 1144.

$$\frac{1144}{7}\times 5\left(2\times 30+53\right)$$

Express \frac{1144}{7}\times 5 as a single fraction.

$$\frac{1144\times 5}{7}\left(2\times 30+53\right)$$

Multiply 1144 and 5 to get 5720.

$$\frac{5720}{7}\left(2\times 30+53\right)$$

Multiply 2 and 30 to get 60.

$$\frac{5720}{7}\left(60+53\right)$$

Add 60 and 53 to get 113.

$$\frac{5720}{7}\times 113$$

Express \frac{5720}{7}\times 113 as a single fraction.

$$\frac{5720\times 113}{7}$$

Multiply 5720 and 113 to get 646360.

$$\frac{646360}{7}$$

Factor

$$\frac{2 ^ {3} \cdot 5 \cdot 11 \cdot 13 \cdot 113}{7} = 92337\frac{1}{7} = 92337.14285714286$$