Solve 22/7left(2^2h-15^2hright)=99

$$\frac{ 22 }{ 7 } \left( { 2 }^{ 2 } h- { 15 }^{ 2 } h \right) = 99$$

Solve for h

$$h=-\frac{63}{442}\approx -0.142533937$$

Steps for Solving Linear Equation

Multiply both sides by \frac{7}{22}, the reciprocal of \frac{22}{7}.

$$2^{2}h-15^{2}h=99\times \frac{7}{22}$$

Express 99\times \frac{7}{22} as a single fraction.

$$2^{2}h-15^{2}h=\frac{99\times 7}{22}$$

Multiply 99 and 7 to get 693.

$$2^{2}h-15^{2}h=\frac{693}{22}$$

Reduce the fraction \frac{693}{22} to lowest terms by extracting and canceling out 11.

$$2^{2}h-15^{2}h=\frac{63}{2}$$

Calculate 2 to the power of 2 and get 4.

$$4h-15^{2}h=\frac{63}{2}$$

Calculate 15 to the power of 2 and get 225.

$$4h-225h=\frac{63}{2}$$

Combine 4h and -225h to get -221h.

$$-221h=\frac{63}{2}$$

Divide both sides by -221.

$$h=\frac{\frac{63}{2}}{-221}$$

Express \frac{\frac{63}{2}}{-221} as a single fraction.

$$h=\frac{63}{2\left(-221\right)}$$

Multiply 2 and -221 to get -442.

$$h=\frac{63}{-442}$$

Fraction \frac{63}{-442} can be rewritten as -\frac{63}{442} by extracting the negative sign.

$$h=-\frac{63}{442}$$