Solve 22/7left(2^2h-1.5^2hright)=99

$$\frac{ 22 }{ 7 } \left( { 2 }^{ 2 } h- { 1.5 }^{ 2 } h \right) = 99$$

Solve for h

$$h=18$$

Steps for Solving Linear Equation

Multiply both sides by \frac{7}{22}, the reciprocal of \frac{22}{7}.

$$2^{2}h-1.5^{2}h=99\times \frac{7}{22}$$

Express 99\times \frac{7}{22} as a single fraction.

$$2^{2}h-1.5^{2}h=\frac{99\times 7}{22}$$

Multiply 99 and 7 to get 693.

$$2^{2}h-1.5^{2}h=\frac{693}{22}$$

Reduce the fraction \frac{693}{22} to lowest terms by extracting and canceling out 11.

$$2^{2}h-1.5^{2}h=\frac{63}{2}$$

Calculate 2 to the power of 2 and get 4.

$$4h-1.5^{2}h=\frac{63}{2}$$

Calculate 1.5 to the power of 2 and get 2.25.

$$4h-2.25h=\frac{63}{2}$$

Combine 4h and -2.25h to get 1.75h.

$$1.75h=\frac{63}{2}$$

Divide both sides by 1.75.

$$h=\frac{\frac{63}{2}}{1.75}$$

Express \frac{\frac{63}{2}}{1.75} as a single fraction.

$$h=\frac{63}{2\times 1.75}$$

Multiply 2 and 1.75 to get 3.5.

$$h=\frac{63}{3.5}$$

Expand \frac{63}{3.5} by multiplying both numerator and the denominator by 10.

$$h=\frac{630}{35}$$

Divide 630 by 35 to get 18.

$$h=18$$