Solve 22/25+2left(0.7*25+6right)div60

$$\frac{ 22 }{ 25 } +2 \left( 0.7 \cdot 25+6 \right) \div 60$$

Evaluate

$$\frac{499}{300}\approx 1.663333333$$

Solution Steps

Multiply 0.7 and 25 to get 17.5.

$$\frac{22}{25}+\frac{2\left(17.5+6\right)}{60}$$

Add 17.5 and 6 to get 23.5.

$$\frac{22}{25}+\frac{2\times 23.5}{60}$$

Multiply 2 and 23.5 to get 47.

$$\frac{22}{25}+\frac{47}{60}$$

Least common multiple of 25 and 60 is 300. Convert \frac{22}{25} and \frac{47}{60} to fractions with denominator 300.

$$\frac{264}{300}+\frac{235}{300}$$

Since \frac{264}{300} and \frac{235}{300} have the same denominator, add them by adding their numerators.

$$\frac{264+235}{300}$$

Add 264 and 235 to get 499.

$$\frac{499}{300}$$

Factor

$$\frac{499}{3 \cdot 2 ^ {2} \cdot 5 ^ {2}} = 1\frac{199}{300} = 1.6633333333333333$$