Solve 200-20x/30geq42

$$\frac{ 200-20x }{ 30 } \geq 42$$

Solve for x

$$x\leq -53$$

Solution Steps

Multiply both sides by 30. Since 30 is positive, the inequality direction remains the same.

$$200-20x\geq 42\times 30$$

Multiply 42 and 30 to get 1260.

$$200-20x\geq 1260$$

Subtract 200 from both sides.

$$-20x\geq 1260-200$$

Subtract 200 from 1260 to get 1060.

$$-20x\geq 1060$$

Divide both sides by -20. Since -20 is negative, the inequality direction is changed.

$$x\leq \frac{1060}{-20}$$

Divide 1060 by -20 to get -53.

$$x\leq -53$$