Solve 20-40/frac{frac{40+20{2}}{((20-15)div2)}}

$$\frac{ 20-40 }{ \frac{ \frac{ 40+20 }{ 2 } }{ ((20-15) \div 2) } }$$

Evaluate

$$-\frac{5}{3}\approx -1.666666667$$

Solution Steps

Subtract 40 from 20 to get -20.

$$\frac{-20}{\frac{\frac{40+20}{2}}{\frac{20-15}{2}}}$$

Divide \frac{40+20}{2} by \frac{20-15}{2} by multiplying \frac{40+20}{2} by the reciprocal of \frac{20-15}{2}.

$$\frac{-20}{\frac{\left(40+20\right)\times 2}{2\left(20-15\right)}}$$

Cancel out 2 in both numerator and denominator.

$$\frac{-20}{\frac{20+40}{20-15}}$$

Add 20 and 40 to get 60.

$$\frac{-20}{\frac{60}{20-15}}$$

Subtract 15 from 20 to get 5.

$$\frac{-20}{\frac{60}{5}}$$

Divide 60 by 5 to get 12.

$$\frac{-20}{12}$$

Reduce the fraction \frac{-20}{12} to lowest terms by extracting and canceling out 4.

$$-\frac{5}{3}$$

Factor

$$-\frac{5}{3} = -1\frac{2}{3} = -1.6666666666666667$$