Solve 20*left(4*12-3*1right)^2/7*13*5*15=

$$\frac{ 20 \times { \left(4 \times 12-3 \times 1 \right) }^{ 2 } }{ 7 \times 13 \times 5 \times 15 } =$$

Evaluate

$$\frac{540}{91}\approx 5.934065934$$

Solution Steps

Cancel out 5 in both numerator and denominator.

$$\frac{4\left(4\times 12-3\right)^{2}}{7\times 13\times 15}$$

Multiply 4 and 12 to get 48.

$$\frac{4\left(48-3\right)^{2}}{7\times 13\times 15}$$

Subtract 3 from 48 to get 45.

$$\frac{4\times 45^{2}}{7\times 13\times 15}$$

Calculate 45 to the power of 2 and get 2025.

$$\frac{4\times 2025}{7\times 13\times 15}$$

Multiply 4 and 2025 to get 8100.

$$\frac{8100}{7\times 13\times 15}$$

Multiply 7 and 13 to get 91.

$$\frac{8100}{91\times 15}$$

Multiply 91 and 15 to get 1365.

$$\frac{8100}{1365}$$

Reduce the fraction \frac{8100}{1365} to lowest terms by extracting and canceling out 15.

$$\frac{540}{91}$$

Factor

$$\frac{2 ^ {2} \cdot 3 ^ {3} \cdot 5}{7 \cdot 13} = 5\frac{85}{91} = 5.934065934065934$$