Solve 2.8-x/10^4=3-x/1.2*10^4

$$\frac{ 2.8-x }{ { 10 }^{ 4 } } = \frac{ 3-x }{ 1.2 \times { 10 }^{ 4 } }$$

Solve for x

$$x=1.8$$

Steps for Solving Linear Equation

Calculate 10 to the power of 4 and get 10000.

$$\frac{2.8-x}{10000}=\frac{3-x}{1.2\times 10^{4}}$$

Calculate 10 to the power of 4 and get 10000.

$$\frac{2.8-x}{10000}=\frac{3-x}{1.2\times 10000}$$

Multiply 1.2 and 10000 to get 12000.

$$\frac{2.8-x}{10000}=\frac{3-x}{12000}$$

Divide each term of 2.8-x by 10000 to get 0.00028-\frac{1}{10000}x.

$$0.00028-\frac{1}{10000}x=\frac{3-x}{12000}$$

Divide each term of 3-x by 12000 to get \frac{1}{4000}-\frac{1}{12000}x.

$$0.00028-\frac{1}{10000}x=\frac{1}{4000}-\frac{1}{12000}x$$

Add \frac{1}{12000}x to both sides.

$$0.00028-\frac{1}{10000}x+\frac{1}{12000}x=\frac{1}{4000}$$

Combine -\frac{1}{10000}x and \frac{1}{12000}x to get -\frac{1}{60000}x.

$$0.00028-\frac{1}{60000}x=\frac{1}{4000}$$

Subtract 0.00028 from both sides.

$$-\frac{1}{60000}x=\frac{1}{4000}-0.00028$$

Convert decimal number 0.00028 to fraction \frac{28}{100000}. Reduce the fraction \frac{28}{100000} to lowest terms by extracting and canceling out 4.

$$-\frac{1}{60000}x=\frac{1}{4000}-\frac{7}{25000}$$

Least common multiple of 4000 and 25000 is 100000. Convert \frac{1}{4000} and \frac{7}{25000} to fractions with denominator 100000.

$$-\frac{1}{60000}x=\frac{25}{100000}-\frac{28}{100000}$$

Since \frac{25}{100000} and \frac{28}{100000} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{1}{60000}x=\frac{25-28}{100000}$$

Subtract 28 from 25 to get -3.

$$-\frac{1}{60000}x=-\frac{3}{100000}$$

Multiply both sides by -60000, the reciprocal of -\frac{1}{60000}.

$$x=-\frac{3}{100000}\left(-60000\right)$$

Express -\frac{3}{100000}\left(-60000\right) as a single fraction.

$$x=\frac{-3\left(-60000\right)}{100000}$$

Multiply -3 and -60000 to get 180000.

$$x=\frac{180000}{100000}$$

Reduce the fraction \frac{180000}{100000} to lowest terms by extracting and canceling out 20000.

$$x=\frac{9}{5}$$