Solve 2+(2/3-4)/1+frac{2{3}}

$$\frac{ 2+( \frac{ 2 }{ 3 } -4) }{ 1+ \frac{ 2 }{ 3 } }$$

Evaluate

$$-\frac{4}{5}=-0.8$$

Solution Steps

Convert 2 to fraction \frac{6}{3}.

$$\frac{\frac{6}{3}+\frac{2}{3}-4}{1+\frac{2}{3}}$$

Since \frac{6}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.

$$\frac{\frac{6+2}{3}-4}{1+\frac{2}{3}}$$

Add 6 and 2 to get 8.

$$\frac{\frac{8}{3}-4}{1+\frac{2}{3}}$$

Convert 4 to fraction \frac{12}{3}.

$$\frac{\frac{8}{3}-\frac{12}{3}}{1+\frac{2}{3}}$$

Since \frac{8}{3} and \frac{12}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{8-12}{3}}{1+\frac{2}{3}}$$

Subtract 12 from 8 to get -4.

$$\frac{-\frac{4}{3}}{1+\frac{2}{3}}$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{-\frac{4}{3}}{\frac{3}{3}+\frac{2}{3}}$$

Since \frac{3}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.

$$\frac{-\frac{4}{3}}{\frac{3+2}{3}}$$

Add 3 and 2 to get 5.

$$\frac{-\frac{4}{3}}{\frac{5}{3}}$$

Divide -\frac{4}{3} by \frac{5}{3} by multiplying -\frac{4}{3} by the reciprocal of \frac{5}{3}.

$$-\frac{4}{3}\times \frac{3}{5}$$

Multiply -\frac{4}{3} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-4\times 3}{3\times 5}$$

Cancel out 3 in both numerator and denominator.

$$\frac{-4}{5}$$

Fraction \frac{-4}{5} can be rewritten as -\frac{4}{5} by extracting the negative sign.

$$-\frac{4}{5}$$

Factor

$$-\frac{4}{5} = -0.8$$