Solve 24^2-12*4+3/3*4-9

$$\frac{ 2 { 4 }^{ 2 } -12 \cdot 4+3 }{ 3 \cdot 4-9 }$$

Evaluate

$$-\frac{13}{3}\approx -4.333333333$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$\frac{2\times 16-12\times 4+3}{3\times 4-9}$$

Multiply 2 and 16 to get 32.

$$\frac{32-12\times 4+3}{3\times 4-9}$$

Multiply 12 and 4 to get 48.

$$\frac{32-48+3}{3\times 4-9}$$

Subtract 48 from 32 to get -16.

$$\frac{-16+3}{3\times 4-9}$$

Add -16 and 3 to get -13.

$$\frac{-13}{3\times 4-9}$$

Multiply 3 and 4 to get 12.

$$\frac{-13}{12-9}$$

Subtract 9 from 12 to get 3.

$$\frac{-13}{3}$$

Fraction \frac{-13}{3} can be rewritten as -\frac{13}{3} by extracting the negative sign.

$$-\frac{13}{3}$$

Factor

$$-\frac{13}{3} = -4\frac{1}{3} = -4.333333333333333$$