Solve 2*4.1^2+4.1-5-2*16-3*4+5/0.1

$$\frac{ 2 \times { 4.1 }^{ 2 } +4.1-5-2 \cdot 16-3 \cdot 4+5 }{ 0.1 }$$

Evaluate

$$-62.8$$

Solution Steps

Calculate 4.1 to the power of 2 and get 16.81.

$$\frac{2\times 16.81+4.1-5-2\times 16-3\times 4+5}{0.1}$$

Multiply 2 and 16.81 to get 33.62.

$$\frac{33.62+4.1-5-2\times 16-3\times 4+5}{0.1}$$

Add 33.62 and 4.1 to get 37.72.

$$\frac{37.72-5-2\times 16-3\times 4+5}{0.1}$$

Subtract 5 from 37.72 to get 32.72.

$$\frac{32.72-2\times 16-3\times 4+5}{0.1}$$

Multiply 2 and 16 to get 32.

$$\frac{32.72-32-3\times 4+5}{0.1}$$

Subtract 32 from 32.72 to get 0.72.

$$\frac{0.72-3\times 4+5}{0.1}$$

Multiply 3 and 4 to get 12.

$$\frac{0.72-12+5}{0.1}$$

Subtract 12 from 0.72 to get -11.28.

$$\frac{-11.28+5}{0.1}$$

Add -11.28 and 5 to get -6.28.

$$\frac{-6.28}{0.1}$$

Expand \frac{-6.28}{0.1} by multiplying both numerator and the denominator by 100.

$$\frac{-628}{10}$$

Reduce the fraction \frac{-628}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{314}{5}$$

Factor

$$-62.8$$