Solve 2*4/3-3/2*frac{4{3}}=-1/8

$$\frac{ 2 \times \frac{ 4 }{ 3 } -3 }{ 2 \times \frac{ 4 }{ 3 } } = - \frac{ 1 }{ 8 }$$

Verify

Solution Steps

Express 2\times \frac{4}{3} as a single fraction.

$$\frac{\frac{2\times 4}{3}-3}{2\times \frac{4}{3}}=-\frac{1}{8}$$

Multiply 2 and 4 to get 8.

$$\frac{\frac{8}{3}-3}{2\times \frac{4}{3}}=-\frac{1}{8}$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{\frac{8}{3}-\frac{9}{3}}{2\times \frac{4}{3}}=-\frac{1}{8}$$

Since \frac{8}{3} and \frac{9}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{8-9}{3}}{2\times \frac{4}{3}}=-\frac{1}{8}$$

Subtract 9 from 8 to get -1.

$$\frac{-\frac{1}{3}}{2\times \frac{4}{3}}=-\frac{1}{8}$$

Express 2\times \frac{4}{3} as a single fraction.

$$\frac{-\frac{1}{3}}{\frac{2\times 4}{3}}=-\frac{1}{8}$$

Multiply 2 and 4 to get 8.

$$\frac{-\frac{1}{3}}{\frac{8}{3}}=-\frac{1}{8}$$

Divide -\frac{1}{3} by \frac{8}{3} by multiplying -\frac{1}{3} by the reciprocal of \frac{8}{3}.

$$-\frac{1}{3}\times \frac{3}{8}=-\frac{1}{8}$$

Multiply -\frac{1}{3} times \frac{3}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-3}{3\times 8}=-\frac{1}{8}$$

Cancel out 3 in both numerator and denominator.

$$\frac{-1}{8}=-\frac{1}{8}$$

Fraction \frac{-1}{8} can be rewritten as -\frac{1}{8} by extracting the negative sign.

$$-\frac{1}{8}=-\frac{1}{8}$$

Compare -\frac{1}{8} and -\frac{1}{8}.

$$\text{true}$$