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\frac{2\sqrt{6}\left(\sqrt{6}+2\right)}{\left(\sqrt{6}-2\right)\left(\sqrt{6}+2\right)}
Rationalize the denominator of \frac{2\sqrt{6}}{\sqrt{6}-2} by multiplying numerator and denominator by \sqrt{6}+2.
\frac{2\sqrt{6}\left(\sqrt{6}+2\right)}{\left(\sqrt{6}\right)^{2}-2^{2}}
Consider \left(\sqrt{6}-2\right)\left(\sqrt{6}+2\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{2\sqrt{6}\left(\sqrt{6}+2\right)}{6-4}
Square \sqrt{6}. Square 2.
\frac{2\sqrt{6}\left(\sqrt{6}+2\right)}{2}
Subtract 4 from 6 to get 2.
\frac{2\left(\sqrt{6}\right)^{2}+4\sqrt{6}}{2}
Use the distributive property to multiply 2\sqrt{6} by \sqrt{6}+2.
\frac{2\times 6+4\sqrt{6}}{2}
The square of \sqrt{6} is 6.
\frac{12+4\sqrt{6}}{2}
Multiply 2 and 6 to get 12.