Solve 24/3-3/2frac{4{3}+3}

$$\frac{ 2 \frac{ 4 }{ 3 } -3 }{ 2 \frac{ 4 }{ 3 } +3 }$$

Evaluate

$$\frac{1}{19}\approx 0.052631579$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{\frac{6+4}{3}-3}{\frac{2\times 3+4}{3}+3}$$

Add 6 and 4 to get 10.

$$\frac{\frac{10}{3}-3}{\frac{2\times 3+4}{3}+3}$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{\frac{10}{3}-\frac{9}{3}}{\frac{2\times 3+4}{3}+3}$$

Since \frac{10}{3} and \frac{9}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{10-9}{3}}{\frac{2\times 3+4}{3}+3}$$

Subtract 9 from 10 to get 1.

$$\frac{\frac{1}{3}}{\frac{2\times 3+4}{3}+3}$$

Multiply 2 and 3 to get 6.

$$\frac{\frac{1}{3}}{\frac{6+4}{3}+3}$$

Add 6 and 4 to get 10.

$$\frac{\frac{1}{3}}{\frac{10}{3}+3}$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{\frac{1}{3}}{\frac{10}{3}+\frac{9}{3}}$$

Since \frac{10}{3} and \frac{9}{3} have the same denominator, add them by adding their numerators.

$$\frac{\frac{1}{3}}{\frac{10+9}{3}}$$

Add 10 and 9 to get 19.

$$\frac{\frac{1}{3}}{\frac{19}{3}}$$

Divide \frac{1}{3} by \frac{19}{3} by multiplying \frac{1}{3} by the reciprocal of \frac{19}{3}.

$$\frac{1}{3}\times \frac{3}{19}$$

Multiply \frac{1}{3} times \frac{3}{19} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 3}{3\times 19}$$

Cancel out 3 in both numerator and denominator.

$$\frac{1}{19}$$

Factor

$$\frac{1}{19} = 0.05263157894736842$$