Solve 2*4-3+5left(2-1right)/6+2

$$\frac{ 2 \cdot 4-3+5 \left( 2-1 \right) }{ 6+2 }$$

Evaluate

$$\frac{5}{4}=1.25$$

Solution Steps

Multiply 2 and 4 to get 8.

$$\frac{8-3+5\left(2-1\right)}{6+2}$$

Subtract 3 from 8 to get 5.

$$\frac{5+5\left(2-1\right)}{6+2}$$

Subtract 1 from 2 to get 1.

$$\frac{5+5\times 1}{6+2}$$

Multiply 5 and 1 to get 5.

$$\frac{5+5}{6+2}$$

Add 5 and 5 to get 10.

$$\frac{10}{6+2}$$

Add 6 and 2 to get 8.

$$\frac{10}{8}$$

Reduce the fraction \frac{10}{8} to lowest terms by extracting and canceling out 2.

$$\frac{5}{4}$$

Factor

$$\frac{5}{2 ^ {2}} = 1\frac{1}{4} = 1.25$$