Solve 2*1-10*1+11-2/sqrt{2^2+-10^2+11^2}

$$\frac{ 2 \cdot 1-10 \cdot 1+11-2 }{ \sqrt{ { 2 }^{ 2 } + { -10 }^{ 2 } + { 11 }^{ 2 } } }$$

Evaluate

$$\frac{1}{15}\approx 0.066666667$$

Solution Steps

Multiply 2 and 1 to get 2.

$$\frac{2-10\times 1+11-2}{\sqrt{2^{2}+\left(-10\right)^{2}+11^{2}}}$$

Multiply 10 and 1 to get 10.

$$\frac{2-10+11-2}{\sqrt{2^{2}+\left(-10\right)^{2}+11^{2}}}$$

Subtract 10 from 2 to get -8.

$$\frac{-8+11-2}{\sqrt{2^{2}+\left(-10\right)^{2}+11^{2}}}$$

Add -8 and 11 to get 3.

$$\frac{3-2}{\sqrt{2^{2}+\left(-10\right)^{2}+11^{2}}}$$

Subtract 2 from 3 to get 1.

$$\frac{1}{\sqrt{2^{2}+\left(-10\right)^{2}+11^{2}}}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{1}{\sqrt{4+\left(-10\right)^{2}+11^{2}}}$$

Calculate -10 to the power of 2 and get 100.

$$\frac{1}{\sqrt{4+100+11^{2}}}$$

Add 4 and 100 to get 104.

$$\frac{1}{\sqrt{104+11^{2}}}$$

Calculate 11 to the power of 2 and get 121.

$$\frac{1}{\sqrt{104+121}}$$

Add 104 and 121 to get 225.

$$\frac{1}{\sqrt{225}}$$

Calculate the square root of 225 and get 15.

$$\frac{1}{15}$$

Factor

$$\frac{1}{3 \cdot 5} = 0.06666666666666667$$