Solve 2*0.9/1.9*pi^2/240*25000*0.7*6.28*1.414*0.5*0.96*2900

$$\frac{ 2 \cdot 0.9 }{ 1.9 } \times \frac{ { \pi }^{ 2 } }{ 240 } \times 25000 \times 0.7 \times 6.28 \times 1.414 \times 0.5 \times 0.96 \times 2900$$

Evaluate

$$\frac{405590346\pi ^{2}}{475}\approx 8427402.660886222$$

Solution Steps

Multiply 2 and 0.9 to get 1.8.

$$\frac{1.8}{1.9}\times \frac{\pi ^{2}}{240}\times 25000\times 0.7\times 6.28\times 1.414\times 0.5\times 0.96\times 2900$$

Expand \frac{1.8}{1.9} by multiplying both numerator and the denominator by 10.

$$\frac{18}{19}\times \frac{\pi ^{2}}{240}\times 25000\times 0.7\times 6.28\times 1.414\times 0.5\times 0.96\times 2900$$

Multiply \frac{18}{19} and 25000 to get \frac{450000}{19}.

$$\frac{450000}{19}\times \frac{\pi ^{2}}{240}\times 0.7\times 6.28\times 1.414\times 0.5\times 0.96\times 2900$$

Multiply \frac{450000}{19} and 0.7 to get \frac{315000}{19}.

$$\frac{315000}{19}\times \frac{\pi ^{2}}{240}\times 6.28\times 1.414\times 0.5\times 0.96\times 2900$$

Multiply \frac{315000}{19} and 6.28 to get \frac{1978200}{19}.

$$\frac{1978200}{19}\times \frac{\pi ^{2}}{240}\times 1.414\times 0.5\times 0.96\times 2900$$

Multiply \frac{1978200}{19} and 1.414 to get \frac{13985874}{95}.

$$\frac{13985874}{95}\times \frac{\pi ^{2}}{240}\times 0.5\times 0.96\times 2900$$

Multiply \frac{13985874}{95} and 0.5 to get \frac{6992937}{95}.

$$\frac{6992937}{95}\times \frac{\pi ^{2}}{240}\times 0.96\times 2900$$

Multiply \frac{6992937}{95} and 0.96 to get \frac{167830488}{2375}.

$$\frac{167830488}{2375}\times \frac{\pi ^{2}}{240}\times 2900$$

Multiply \frac{167830488}{2375} and 2900 to get \frac{19468336608}{95}.

$$\frac{19468336608}{95}\times \frac{\pi ^{2}}{240}$$

Multiply \frac{19468336608}{95} times \frac{\pi ^{2}}{240} by multiplying numerator times numerator and denominator times denominator.

$$\frac{19468336608\pi ^{2}}{95\times 240}$$

Cancel out 48 in both numerator and denominator.

$$\frac{405590346\pi ^{2}}{5\times 95}$$

Multiply 5 and 95 to get 475.

$$\frac{405590346\pi ^{2}}{475}$$