Solve for x
x=\frac{2y}{3\left(5y+1\right)}
y\neq 0\text{ and }y\neq -\frac{1}{5}
Solve for y
y=-\frac{3x}{15x-2}
x\neq 0\text{ and }x\neq \frac{2}{15}
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y\times 2-x\times 3=15xy
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by xy, the least common multiple of x,y.
y\times 2-x\times 3-15xy=0
Subtract 15xy from both sides.
-x\times 3-15xy=-y\times 2
Subtract y\times 2 from both sides. Anything subtracted from zero gives its negation.
-3x-15xy=-y\times 2
Multiply -1 and 3 to get -3.
-3x-15xy=-2y
Multiply -1 and 2 to get -2.
\left(-3-15y\right)x=-2y
Combine all terms containing x.
\left(-15y-3\right)x=-2y
The equation is in standard form.
\frac{\left(-15y-3\right)x}{-15y-3}=-\frac{2y}{-15y-3}
Divide both sides by -15y-3.
x=-\frac{2y}{-15y-3}
Dividing by -15y-3 undoes the multiplication by -15y-3.
x=\frac{2y}{3\left(5y+1\right)}
Divide -2y by -15y-3.
x=\frac{2y}{3\left(5y+1\right)}\text{, }x\neq 0
Variable x cannot be equal to 0.
y\times 2-x\times 3=15xy
Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by xy, the least common multiple of x,y.
y\times 2-x\times 3-15xy=0
Subtract 15xy from both sides.
y\times 2-15xy=x\times 3
Add x\times 3 to both sides. Anything plus zero gives itself.
\left(2-15x\right)y=x\times 3
Combine all terms containing y.
\left(2-15x\right)y=3x
The equation is in standard form.
\frac{\left(2-15x\right)y}{2-15x}=\frac{3x}{2-15x}
Divide both sides by 2-15x.
y=\frac{3x}{2-15x}
Dividing by 2-15x undoes the multiplication by 2-15x.
y=\frac{3x}{2-15x}\text{, }y\neq 0
Variable y cannot be equal to 0.
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