Solve 2/3+6divsqrt[3]{8}*3x+y3+x5

$$\frac{ 2 }{ 3+6 } \div \sqrt[3]{ 8 } \times 3x+y3+x5$$

Evaluate

$$\frac{x}{3}+x_{5}+y_{3}$$

Solution Steps

Express \frac{\frac{2}{3+6}}{\sqrt[3]{8}} as a single fraction.

$$\frac{2}{\left(3+6\right)\sqrt[3]{8}}\times 3x+y_{3}+x_{5}$$

Add 3 and 6 to get 9.

$$\frac{2}{9\sqrt[3]{8}}\times 3x+y_{3}+x_{5}$$

Calculate \sqrt[3]{8} and get 2.

$$\frac{2}{9\times 2}\times 3x+y_{3}+x_{5}$$

Multiply 9 and 2 to get 18.

$$\frac{2}{18}\times 3x+y_{3}+x_{5}$$

Reduce the fraction \frac{2}{18} to lowest terms by extracting and canceling out 2.

$$\frac{1}{9}\times 3x+y_{3}+x_{5}$$

Multiply \frac{1}{9} and 3 to get \frac{1}{3}.

$$\frac{1}{3}x+y_{3}+x_{5}$$

Differentiate w.r.t. x

$$\frac{1}{3} = 0.3333333333333333$$