Solve 2/3x-3geq12

$$\frac{ 2 }{ 3 } x-3 \geq 12$$

Solve for x

$$x\geq \frac{45}{2}$$

Solution Steps

Add 3 to both sides.

$$\frac{2}{3}x\geq 12+3$$

Add 12 and 3 to get 15.

$$\frac{2}{3}x\geq 15$$

Multiply both sides by \frac{3}{2}, the reciprocal of \frac{2}{3}. Since \frac{2}{3} is positive, the inequality direction remains the same.

$$x\geq 15\times \frac{3}{2}$$

Express 15\times \frac{3}{2} as a single fraction.

$$x\geq \frac{15\times 3}{2}$$

Multiply 15 and 3 to get 45.

$$x\geq \frac{45}{2}$$