Solve 2/3x=5-3/5y

$$\frac{ 2 }{ 3 } x = 5- \frac{ 3 }{ 5 } y$$

Solve for x

$$x=-\frac{9y}{10}+\frac{15}{2}$$

Steps for Solving Linear Equation

The equation is in standard form.

$$\frac{2}{3}x=-\frac{3y}{5}+5$$

Divide both sides of the equation by \frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{2}{3}x}{\frac{2}{3}}=\frac{-\frac{3y}{5}+5}{\frac{2}{3}}$$

Dividing by \frac{2}{3} undoes the multiplication by \frac{2}{3}.

$$x=\frac{-\frac{3y}{5}+5}{\frac{2}{3}}$$

Divide 5-\frac{3y}{5} by \frac{2}{3} by multiplying 5-\frac{3y}{5} by the reciprocal of \frac{2}{3}.

$$x=-\frac{9y}{10}+\frac{15}{2}$$

Solve for y

$$y=-\frac{10x}{9}+\frac{25}{3}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$5-\frac{3}{5}y=\frac{2}{3}x$$

Subtract 5 from both sides.

$$-\frac{3}{5}y=\frac{2}{3}x-5$$

The equation is in standard form.

$$-\frac{3}{5}y=\frac{2x}{3}-5$$

Divide both sides of the equation by -\frac{3}{5}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{3}{5}y}{-\frac{3}{5}}=\frac{\frac{2x}{3}-5}{-\frac{3}{5}}$$

Dividing by -\frac{3}{5} undoes the multiplication by -\frac{3}{5}.

$$y=\frac{\frac{2x}{3}-5}{-\frac{3}{5}}$$

Divide \frac{2x}{3}-5 by -\frac{3}{5} by multiplying \frac{2x}{3}-5 by the reciprocal of -\frac{3}{5}.

$$y=-\frac{10x}{9}+\frac{25}{3}$$