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\frac{2}{3}-8x+\frac{1}{2}x=3
Add \frac{1}{2}x to both sides.
\frac{2}{3}-\frac{15}{2}x=3
Combine -8x and \frac{1}{2}x to get -\frac{15}{2}x.
-\frac{15}{2}x=3-\frac{2}{3}
Subtract \frac{2}{3} from both sides.
-\frac{15}{2}x=\frac{9}{3}-\frac{2}{3}
Convert 3 to fraction \frac{9}{3}.
-\frac{15}{2}x=\frac{9-2}{3}
Since \frac{9}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.
-\frac{15}{2}x=\frac{7}{3}
Subtract 2 from 9 to get 7.
x=\frac{7}{3}\left(-\frac{2}{15}\right)
Multiply both sides by -\frac{2}{15}, the reciprocal of -\frac{15}{2}.
x=\frac{7\left(-2\right)}{3\times 15}
Multiply \frac{7}{3} times -\frac{2}{15} by multiplying numerator times numerator and denominator times denominator.
x=\frac{-14}{45}
Do the multiplications in the fraction \frac{7\left(-2\right)}{3\times 15}.
x=-\frac{14}{45}
Fraction \frac{-14}{45} can be rewritten as -\frac{14}{45} by extracting the negative sign.