Solve 2/3*3/4=2*3/3*4=6/12=

$$\frac{ 2 }{ 3 } \times \frac{ 3 }{ 4 } = \frac{ 2 \times 3 }{ 3 \times 4 } = \frac{ 6 }{ 12 } =$$

Verify

Solution Steps

Multiply \frac{2}{3} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 3}{3\times 4}=\frac{2\times 3}{3\times 4}\text{ and }\frac{2\times 3}{3\times 4}=\frac{6}{12}$$

Cancel out 3 in both numerator and denominator.

$$\frac{2}{4}=\frac{2\times 3}{3\times 4}\text{ and }\frac{2\times 3}{3\times 4}=\frac{6}{12}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{1}{2}=\frac{2\times 3}{3\times 4}\text{ and }\frac{2\times 3}{3\times 4}=\frac{6}{12}$$

Cancel out 2\times 3 in both numerator and denominator.

$$\frac{1}{2}=\frac{1}{2}\text{ and }\frac{2\times 3}{3\times 4}=\frac{6}{12}$$

Compare \frac{1}{2} and \frac{1}{2}.

$$\text{true}\text{ and }\frac{2\times 3}{3\times 4}=\frac{6}{12}$$

Cancel out 2\times 3 in both numerator and denominator.

$$\text{true}\text{ and }\frac{1}{2}=\frac{6}{12}$$

Reduce the fraction \frac{6}{12} to lowest terms by extracting and canceling out 6.

$$\text{true}\text{ and }\frac{1}{2}=\frac{1}{2}$$

Compare \frac{1}{2} and \frac{1}{2}.

$$\text{true}\text{ and }\text{true}$$

The conjunction of \text{true} and \text{true} is \text{true}.

$$\text{true}$$