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\frac{2\left(2-\sqrt{5}\right)}{\left(2+\sqrt{5}\right)\left(2-\sqrt{5}\right)}
Rationalize the denominator of \frac{2}{2+\sqrt{5}} by multiplying numerator and denominator by 2-\sqrt{5}.
\frac{2\left(2-\sqrt{5}\right)}{2^{2}-\left(\sqrt{5}\right)^{2}}
Consider \left(2+\sqrt{5}\right)\left(2-\sqrt{5}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{2\left(2-\sqrt{5}\right)}{4-5}
Square 2. Square \sqrt{5}.
\frac{2\left(2-\sqrt{5}\right)}{-1}
Subtract 5 from 4 to get -1.
-2\left(2-\sqrt{5}\right)
Anything divided by -1 gives its opposite.
-4+2\sqrt{5}
Use the distributive property to multiply -2 by 2-\sqrt{5}.