Solve 19/56-1/72-10/84+8/63==

$$\frac{ 19 }{ 56 } - \frac{ 1 }{ 72 } - \frac{ 10 }{ 84 } + \frac{ 8 }{ 63 } ==$$

Evaluate

$$\frac{1}{3}\approx 0.333333333$$

Solution Steps

Least common multiple of 56 and 72 is 504. Convert \frac{19}{56} and \frac{1}{72} to fractions with denominator 504.

$$\frac{171}{504}-\frac{7}{504}-\frac{10}{84}+\frac{8}{63}$$

Since \frac{171}{504} and \frac{7}{504} have the same denominator, subtract them by subtracting their numerators.

$$\frac{171-7}{504}-\frac{10}{84}+\frac{8}{63}$$

Subtract 7 from 171 to get 164.

$$\frac{164}{504}-\frac{10}{84}+\frac{8}{63}$$

Reduce the fraction \frac{164}{504} to lowest terms by extracting and canceling out 4.

$$\frac{41}{126}-\frac{10}{84}+\frac{8}{63}$$

Reduce the fraction \frac{10}{84} to lowest terms by extracting and canceling out 2.

$$\frac{41}{126}-\frac{5}{42}+\frac{8}{63}$$

Least common multiple of 126 and 42 is 126. Convert \frac{41}{126} and \frac{5}{42} to fractions with denominator 126.

$$\frac{41}{126}-\frac{15}{126}+\frac{8}{63}$$

Since \frac{41}{126} and \frac{15}{126} have the same denominator, subtract them by subtracting their numerators.

$$\frac{41-15}{126}+\frac{8}{63}$$

Subtract 15 from 41 to get 26.

$$\frac{26}{126}+\frac{8}{63}$$

Reduce the fraction \frac{26}{126} to lowest terms by extracting and canceling out 2.

$$\frac{13}{63}+\frac{8}{63}$$

Since \frac{13}{63} and \frac{8}{63} have the same denominator, add them by adding their numerators.

$$\frac{13+8}{63}$$

Add 13 and 8 to get 21.

$$\frac{21}{63}$$

Reduce the fraction \frac{21}{63} to lowest terms by extracting and canceling out 21.

$$\frac{1}{3}$$

Factor

$$\frac{1}{3} = 0.3333333333333333$$