Solve for x
x=10
x=-10
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\frac{180}{360}x^{2}=50
Cancel out \pi on both sides.
\frac{1}{2}x^{2}=50
Reduce the fraction \frac{180}{360} to lowest terms by extracting and canceling out 180.
\frac{1}{2}x^{2}-50=0
Subtract 50 from both sides.
x^{2}-100=0
Multiply both sides by 2.
\left(x-10\right)\left(x+10\right)=0
Consider x^{2}-100. Rewrite x^{2}-100 as x^{2}-10^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=10 x=-10
To find equation solutions, solve x-10=0 and x+10=0.
\frac{180}{360}x^{2}=50
Cancel out \pi on both sides.
\frac{1}{2}x^{2}=50
Reduce the fraction \frac{180}{360} to lowest terms by extracting and canceling out 180.
x^{2}=50\times 2
Multiply both sides by 2, the reciprocal of \frac{1}{2}.
x^{2}=100
Multiply 50 and 2 to get 100.
x=10 x=-10
Take the square root of both sides of the equation.
\frac{180}{360}x^{2}=50
Cancel out \pi on both sides.
\frac{1}{2}x^{2}=50
Reduce the fraction \frac{180}{360} to lowest terms by extracting and canceling out 180.
\frac{1}{2}x^{2}-50=0
Subtract 50 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times \frac{1}{2}\left(-50\right)}}{2\times \frac{1}{2}}
This equation is in standard form: ax^{2}+bx+c=0. Substitute \frac{1}{2} for a, 0 for b, and -50 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times \frac{1}{2}\left(-50\right)}}{2\times \frac{1}{2}}
Square 0.
x=\frac{0±\sqrt{-2\left(-50\right)}}{2\times \frac{1}{2}}
Multiply -4 times \frac{1}{2}.
x=\frac{0±\sqrt{100}}{2\times \frac{1}{2}}
Multiply -2 times -50.
x=\frac{0±10}{2\times \frac{1}{2}}
Take the square root of 100.
x=\frac{0±10}{1}
Multiply 2 times \frac{1}{2}.
x=10
Now solve the equation x=\frac{0±10}{1} when ± is plus.
x=-10
Now solve the equation x=\frac{0±10}{1} when ± is minus.
x=10 x=-10
The equation is now solved.
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