Solve 18/7*(4/9+15/18)

$$\frac{ 18 }{ 7 } \times ( \frac{ 4 }{ 9 } + \frac{ 15 }{ 18 } )$$

Evaluate

$$\frac{23}{7}\approx 3.285714286$$

Solution Steps

Reduce the fraction \frac{15}{18} to lowest terms by extracting and canceling out 3.

$$\frac{18}{7}\left(\frac{4}{9}+\frac{5}{6}\right)$$

Least common multiple of 9 and 6 is 18. Convert \frac{4}{9} and \frac{5}{6} to fractions with denominator 18.

$$\frac{18}{7}\left(\frac{8}{18}+\frac{15}{18}\right)$$

Since \frac{8}{18} and \frac{15}{18} have the same denominator, add them by adding their numerators.

$$\frac{18}{7}\times \frac{8+15}{18}$$

Add 8 and 15 to get 23.

$$\frac{18}{7}\times \frac{23}{18}$$

Multiply \frac{18}{7} times \frac{23}{18} by multiplying numerator times numerator and denominator times denominator.

$$\frac{18\times 23}{7\times 18}$$

Cancel out 18 in both numerator and denominator.

$$\frac{23}{7}$$

Factor

$$\frac{23}{7} = 3\frac{2}{7} = 3.2857142857142856$$