Solve 16/3+x=4/3-x

$$\frac{ 16 }{ 3+x } = \frac{ 4 }{ 3-x }$$

Solve for x

$$x = \frac{9}{5} = 1\frac{4}{5} = 1.8$$

Steps for Solving Linear Equation

Variable x cannot be equal to any of the values -3,3 since division by zero is not defined. Multiply both sides of the equation by \left(x-3\right)\left(x+3\right), the least common multiple of 3+x,3-x.

$$\left(x-3\right)\times 16=-\left(3+x\right)\times 4$$

Use the distributive property to multiply x-3 by 16.

$$16x-48=-\left(3+x\right)\times 4$$

Multiply -1 and 4 to get -4.

$$16x-48=-4\left(3+x\right)$$

Use the distributive property to multiply -4 by 3+x.

$$16x-48=-12-4x$$

Add 4x to both sides.

$$16x-48+4x=-12$$

Combine 16x and 4x to get 20x.

$$20x-48=-12$$

Add 48 to both sides.

$$20x=-12+48$$

Add -12 and 48 to get 36.

$$20x=36$$

Divide both sides by 20.

$$x=\frac{36}{20}$$

Reduce the fraction \frac{36}{20} to lowest terms by extracting and canceling out 4.

$$x=\frac{9}{5}$$