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\frac{64x^{4}-25}{100}
Factor out \frac{1}{100}.
\left(8x^{2}-5\right)\left(8x^{2}+5\right)
Consider 64x^{4}-25. Rewrite 64x^{4}-25 as \left(8x^{2}\right)^{2}-5^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{\left(8x^{2}-5\right)\left(8x^{2}+5\right)}{100}
Rewrite the complete factored expression. The following polynomials are not factored since they do not have any rational roots: 8x^{2}-5,8x^{2}+5.