Solve 15/2*11-3=10/4*11-5

$$\frac{ 15 }{ 2 \cdot 11-3 } = \frac{ 10 }{ 4 \cdot 11-5 }$$

Verify

Solution Steps

Multiply 2 and 11 to get 22.

$$\frac{15}{22-3}=\frac{10}{4\times 11-5}$$

Subtract 3 from 22 to get 19.

$$\frac{15}{19}=\frac{10}{4\times 11-5}$$

Multiply 4 and 11 to get 44.

$$\frac{15}{19}=\frac{10}{44-5}$$

Subtract 5 from 44 to get 39.

$$\frac{15}{19}=\frac{10}{39}$$

Least common multiple of 19 and 39 is 741. Convert \frac{15}{19} and \frac{10}{39} to fractions with denominator 741.

$$\frac{585}{741}=\frac{190}{741}$$

Compare \frac{585}{741} and \frac{190}{741}.

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