Solve 15/2*1.1-3=10/4*1.1-5

$$\frac{ 15 }{ 2 \cdot 1.1-3 } = \frac{ 10 }{ 4 \cdot 1.1-5 }$$

Verify

Solution Steps

Multiply 2 and 1.1 to get 2.2.

$$\frac{15}{2.2-3}=\frac{10}{4\times 1.1-5}$$

Subtract 3 from 2.2 to get -0.8.

$$\frac{15}{-0.8}=\frac{10}{4\times 1.1-5}$$

Expand \frac{15}{-0.8} by multiplying both numerator and the denominator by 10.

$$\frac{150}{-8}=\frac{10}{4\times 1.1-5}$$

Reduce the fraction \frac{150}{-8} to lowest terms by extracting and canceling out 2.

$$-\frac{75}{4}=\frac{10}{4\times 1.1-5}$$

Multiply 4 and 1.1 to get 4.4.

$$-\frac{75}{4}=\frac{10}{4.4-5}$$

Subtract 5 from 4.4 to get -0.6.

$$-\frac{75}{4}=\frac{10}{-0.6}$$

Expand \frac{10}{-0.6} by multiplying both numerator and the denominator by 10.

$$-\frac{75}{4}=\frac{100}{-6}$$

Reduce the fraction \frac{100}{-6} to lowest terms by extracting and canceling out 2.

$$-\frac{75}{4}=-\frac{50}{3}$$

Least common multiple of 4 and 3 is 12. Convert -\frac{75}{4} and -\frac{50}{3} to fractions with denominator 12.

$$-\frac{225}{12}=-\frac{200}{12}$$

Compare -\frac{225}{12} and -\frac{200}{12}.

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