Solve 15/2*1*1-3=10/4*1*1*5

$$\frac{ 15 }{ 2 \cdot 1 \cdot 1-3 } = \frac{ 10 }{ 4 \cdot 1 \cdot 1 \cdot 5 }$$

Verify

Solution Steps

Multiply 2 and 1 to get 2.

$$\frac{15}{2\times 1-3}=\frac{10}{4\times 1\times 1\times 5}$$

Multiply 2 and 1 to get 2.

$$\frac{15}{2-3}=\frac{10}{4\times 1\times 1\times 5}$$

Subtract 3 from 2 to get -1.

$$\frac{15}{-1}=\frac{10}{4\times 1\times 1\times 5}$$

Fraction \frac{15}{-1} can be rewritten as -15 by extracting the negative sign.

$$-15=\frac{10}{4\times 1\times 1\times 5}$$

Multiply 4 and 1 to get 4.

$$-15=\frac{10}{4\times 1\times 5}$$

Multiply 4 and 1 to get 4.

$$-15=\frac{10}{4\times 5}$$

Multiply 4 and 5 to get 20.

$$-15=\frac{10}{20}$$

Reduce the fraction \frac{10}{20} to lowest terms by extracting and canceling out 10.

$$-15=\frac{1}{2}$$

Convert -15 to fraction -\frac{30}{2}.

$$-\frac{30}{2}=\frac{1}{2}$$

Compare -\frac{30}{2} and \frac{1}{2}.

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