Solve 144/12+8-16-3+12*5-8/2+4

$$\frac{ 144 }{ 12 } +8-16-3+12 \cdot 5- \frac{ 8 }{ 2 } +4$$

Evaluate

$$61$$

Solution Steps

Divide 144 by 12 to get 12.

$$12+8-16-3+12\times 5-\frac{8}{2}+4$$

Add 12 and 8 to get 20.

$$20-16-3+12\times 5-\frac{8}{2}+4$$

Subtract 16 from 20 to get 4.

$$4-3+12\times 5-\frac{8}{2}+4$$

Subtract 3 from 4 to get 1.

$$1+12\times 5-\frac{8}{2}+4$$

Multiply 12 and 5 to get 60.

$$1+60-\frac{8}{2}+4$$

Add 1 and 60 to get 61.

$$61-\frac{8}{2}+4$$

Divide 8 by 2 to get 4.

$$61-4+4$$

Subtract 4 from 61 to get 57.

$$57+4$$

Add 57 and 4 to get 61.

$$61$$

Factor

$$61$$