Solve 14-1/3-1/2-frac{1{3}}

$$\frac{ 14- \frac{ 1 }{ 3 } -1 }{ 2- \frac{ 1 }{ 3 } }$$

Evaluate

$$\frac{38}{5}=7.6$$

Solution Steps

Convert 14 to fraction \frac{42}{3}.

$$\frac{\frac{42}{3}-\frac{1}{3}-1}{2-\frac{1}{3}}$$

Since \frac{42}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{42-1}{3}-1}{2-\frac{1}{3}}$$

Subtract 1 from 42 to get 41.

$$\frac{\frac{41}{3}-1}{2-\frac{1}{3}}$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{\frac{41}{3}-\frac{3}{3}}{2-\frac{1}{3}}$$

Since \frac{41}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{41-3}{3}}{2-\frac{1}{3}}$$

Subtract 3 from 41 to get 38.

$$\frac{\frac{38}{3}}{2-\frac{1}{3}}$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{\frac{38}{3}}{\frac{6}{3}-\frac{1}{3}}$$

Since \frac{6}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{38}{3}}{\frac{6-1}{3}}$$

Subtract 1 from 6 to get 5.

$$\frac{\frac{38}{3}}{\frac{5}{3}}$$

Divide \frac{38}{3} by \frac{5}{3} by multiplying \frac{38}{3} by the reciprocal of \frac{5}{3}.

$$\frac{38}{3}\times \frac{3}{5}$$

Multiply \frac{38}{3} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{38\times 3}{3\times 5}$$

Cancel out 3 in both numerator and denominator.

$$\frac{38}{5}$$

Factor

$$\frac{2 \cdot 19}{5} = 7\frac{3}{5} = 7.6$$