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\frac{13\left(4-\sqrt{3}\right)}{\left(4+\sqrt{3}\right)\left(4-\sqrt{3}\right)}
Rationalize the denominator of \frac{13}{4+\sqrt{3}} by multiplying numerator and denominator by 4-\sqrt{3}.
\frac{13\left(4-\sqrt{3}\right)}{4^{2}-\left(\sqrt{3}\right)^{2}}
Consider \left(4+\sqrt{3}\right)\left(4-\sqrt{3}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{13\left(4-\sqrt{3}\right)}{16-3}
Square 4. Square \sqrt{3}.
\frac{13\left(4-\sqrt{3}\right)}{13}
Subtract 3 from 16 to get 13.
4-\sqrt{3}
Cancel out 13 and 13.