Solve 125/100-(0.75-6/10*25/90)div42/90

$$\frac{ 125 }{ 100 } -(0.75- \frac{ 6 }{ 10 } \times \frac{ 25 }{ 90 } ) \div \frac{ 42 }{ 90 }$$

Evaluate

$$0$$

Solution Steps

Reduce the fraction \frac{125}{100} to lowest terms by extracting and canceling out 25.

$$\frac{5}{4}-\frac{0.75-\frac{6}{10}\times \frac{25}{90}}{\frac{42}{90}}$$

Reduce the fraction \frac{6}{10} to lowest terms by extracting and canceling out 2.

$$\frac{5}{4}-\frac{0.75-\frac{3}{5}\times \frac{25}{90}}{\frac{42}{90}}$$

Reduce the fraction \frac{25}{90} to lowest terms by extracting and canceling out 5.

$$\frac{5}{4}-\frac{0.75-\frac{3}{5}\times \frac{5}{18}}{\frac{42}{90}}$$

Multiply \frac{3}{5} times \frac{5}{18} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5}{4}-\frac{0.75-\frac{3\times 5}{5\times 18}}{\frac{42}{90}}$$

Cancel out 5 in both numerator and denominator.

$$\frac{5}{4}-\frac{0.75-\frac{3}{18}}{\frac{42}{90}}$$

Reduce the fraction \frac{3}{18} to lowest terms by extracting and canceling out 3.

$$\frac{5}{4}-\frac{0.75-\frac{1}{6}}{\frac{42}{90}}$$

Convert decimal number 0.75 to fraction \frac{75}{100}. Reduce the fraction \frac{75}{100} to lowest terms by extracting and canceling out 25.

$$\frac{5}{4}-\frac{\frac{3}{4}-\frac{1}{6}}{\frac{42}{90}}$$

Least common multiple of 4 and 6 is 12. Convert \frac{3}{4} and \frac{1}{6} to fractions with denominator 12.

$$\frac{5}{4}-\frac{\frac{9}{12}-\frac{2}{12}}{\frac{42}{90}}$$

Since \frac{9}{12} and \frac{2}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5}{4}-\frac{\frac{9-2}{12}}{\frac{42}{90}}$$

Subtract 2 from 9 to get 7.

$$\frac{5}{4}-\frac{\frac{7}{12}}{\frac{42}{90}}$$

Reduce the fraction \frac{42}{90} to lowest terms by extracting and canceling out 6.

$$\frac{5}{4}-\frac{\frac{7}{12}}{\frac{7}{15}}$$

Divide \frac{7}{12} by \frac{7}{15} by multiplying \frac{7}{12} by the reciprocal of \frac{7}{15}.

$$\frac{5}{4}-\frac{7}{12}\times \frac{15}{7}$$

Multiply \frac{7}{12} times \frac{15}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5}{4}-\frac{7\times 15}{12\times 7}$$

Cancel out 7 in both numerator and denominator.

$$\frac{5}{4}-\frac{15}{12}$$

Reduce the fraction \frac{15}{12} to lowest terms by extracting and canceling out 3.

$$\frac{5}{4}-\frac{5}{4}$$

Subtract \frac{5}{4} from \frac{5}{4} to get 0.

$$0$$

Factor

$$0$$