Solve 1220/30+1840/60-4030/20

$$\frac{ 1220 }{ 30 } + \frac{ 1840 }{ 60 } - \frac{ 4030 }{ 20 }$$

Evaluate

$$-\frac{781}{6}\approx -130.166666667$$

Solution Steps

Reduce the fraction \frac{1220}{30} to lowest terms by extracting and canceling out 10.

$$\frac{122}{3}+\frac{1840}{60}-\frac{4030}{20}$$

Reduce the fraction \frac{1840}{60} to lowest terms by extracting and canceling out 20.

$$\frac{122}{3}+\frac{92}{3}-\frac{4030}{20}$$

Since \frac{122}{3} and \frac{92}{3} have the same denominator, add them by adding their numerators.

$$\frac{122+92}{3}-\frac{4030}{20}$$

Add 122 and 92 to get 214.

$$\frac{214}{3}-\frac{4030}{20}$$

Reduce the fraction \frac{4030}{20} to lowest terms by extracting and canceling out 10.

$$\frac{214}{3}-\frac{403}{2}$$

Least common multiple of 3 and 2 is 6. Convert \frac{214}{3} and \frac{403}{2} to fractions with denominator 6.

$$\frac{428}{6}-\frac{1209}{6}$$

Since \frac{428}{6} and \frac{1209}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{428-1209}{6}$$

Subtract 1209 from 428 to get -781.

$$-\frac{781}{6}$$

Factor

$$-\frac{781}{6} = -130\frac{1}{6} = -130.16666666666666$$