Solve 12-(-2)(4)/4+3left(4-6right)^2

$$\frac{ 12-(-2)(4) }{ 4 } +3 { \left(4-6 \right) }^{ 2 }$$

Evaluate

$$17$$

Solution Steps

Multiply -2 and 4 to get -8.

$$\frac{12-\left(-8\right)}{4}+3\left(4-6\right)^{2}$$

The opposite of -8 is 8.

$$\frac{12+8}{4}+3\left(4-6\right)^{2}$$

Add 12 and 8 to get 20.

$$\frac{20}{4}+3\left(4-6\right)^{2}$$

Divide 20 by 4 to get 5.

$$5+3\left(4-6\right)^{2}$$

Subtract 6 from 4 to get -2.

$$5+3\left(-2\right)^{2}$$

Calculate -2 to the power of 2 and get 4.

$$5+3\times 4$$

Multiply 3 and 4 to get 12.

$$5+12$$

Add 5 and 12 to get 17.

$$17$$

Factor

$$17$$