Solve 12!/2!(12-2)!(0.44^2)(0.56^10)

$$\frac{ 12 ! }{ 2 ! (12-2) ! } ( { 0.44 }^{ 2 } )( { 0.56 }^{ 10 } )$$

Evaluate

$$0.038755162174745084952576$$

Solution Steps

The factorial of 12 is 479001600.

$$\frac{479001600}{2!\left(12-2\right)!}\times 0.44^{2}\times 0.56^{10}$$

The factorial of 2 is 2.

$$\frac{479001600}{2\left(12-2\right)!}\times 0.44^{2}\times 0.56^{10}$$

Subtract 2 from 12 to get 10.

$$\frac{479001600}{2\times 10!}\times 0.44^{2}\times 0.56^{10}$$

The factorial of 10 is 3628800.

$$\frac{479001600}{2\times 3628800}\times 0.44^{2}\times 0.56^{10}$$

Multiply 2 and 3628800 to get 7257600.

$$\frac{479001600}{7257600}\times 0.44^{2}\times 0.56^{10}$$

Divide 479001600 by 7257600 to get 66.

$$66\times 0.44^{2}\times 0.56^{10}$$

Calculate 0.44 to the power of 2 and get 0.1936.

$$66\times 0.1936\times 0.56^{10}$$

Multiply 66 and 0.1936 to get 12.7776.

$$12.7776\times 0.56^{10}$$

Calculate 0.56 to the power of 10 and get 0.00303305489096114176.

$$12.7776\times 0.00303305489096114176$$

Multiply 12.7776 and 0.00303305489096114176 to get 0.038755162174745084952576.

$$0.038755162174745084952576$$

Factor

$$\frac{3 \cdot 2 ^ {11} \cdot 7 ^ {10} \cdot 11 ^ {3}}{5 ^ {24}} = 0.03875516217474508$$