Solve 11-0.3x/2leq5

$$\frac{ 11-0.3x }{ 2 } \leq 5$$

Solve for x

$$x\geq \frac{10}{3}$$

Solution Steps

Multiply both sides by 2. Since 2 is positive, the inequality direction remains the same.

$$11-0.3x\leq 5\times 2$$

Multiply 5 and 2 to get 10.

$$11-0.3x\leq 10$$

Subtract 11 from both sides.

$$-0.3x\leq 10-11$$

Subtract 11 from 10 to get -1.

$$-0.3x\leq -1$$

Divide both sides by -0.3. Since -0.3 is negative, the inequality direction is changed.

$$x\geq \frac{-1}{-0.3}$$

Expand \frac{-1}{-0.3} by multiplying both numerator and the denominator by 10.

$$x\geq \frac{-10}{-3}$$

Fraction \frac{-10}{-3} can be simplified to \frac{10}{3} by removing the negative sign from both the numerator and the denominator.

$$x\geq \frac{10}{3}$$