Solve 11/3431/41+11/107/21=frac{19}{41}

$$\frac{ 11 }{ 34 } \frac{ 31 }{ 41 } + \frac{ 11 }{ 10 } \frac{ 7 }{ 21 } = \frac{ 19 }{ 41 }$$

Verify

Solution Steps

Multiply \frac{11}{34} times \frac{31}{41} by multiplying numerator times numerator and denominator times denominator.

$$\frac{11\times 31}{34\times 41}+\frac{11}{10}\times \frac{7}{21}=\frac{19}{41}$$

Do the multiplications in the fraction \frac{11\times 31}{34\times 41}.

$$\frac{341}{1394}+\frac{11}{10}\times \frac{7}{21}=\frac{19}{41}$$

Reduce the fraction \frac{7}{21} to lowest terms by extracting and canceling out 7.

$$\frac{341}{1394}+\frac{11}{10}\times \frac{1}{3}=\frac{19}{41}$$

Multiply \frac{11}{10} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{341}{1394}+\frac{11\times 1}{10\times 3}=\frac{19}{41}$$

Do the multiplications in the fraction \frac{11\times 1}{10\times 3}.

$$\frac{341}{1394}+\frac{11}{30}=\frac{19}{41}$$

Least common multiple of 1394 and 30 is 20910. Convert \frac{341}{1394} and \frac{11}{30} to fractions with denominator 20910.

$$\frac{5115}{20910}+\frac{7667}{20910}=\frac{19}{41}$$

Since \frac{5115}{20910} and \frac{7667}{20910} have the same denominator, add them by adding their numerators.

$$\frac{5115+7667}{20910}=\frac{19}{41}$$

Add 5115 and 7667 to get 12782.

$$\frac{12782}{20910}=\frac{19}{41}$$

Reduce the fraction \frac{12782}{20910} to lowest terms by extracting and canceling out 2.

$$\frac{6391}{10455}=\frac{19}{41}$$

Least common multiple of 10455 and 41 is 10455. Convert \frac{6391}{10455} and \frac{19}{41} to fractions with denominator 10455.

$$\frac{6391}{10455}=\frac{4845}{10455}$$

Compare \frac{6391}{10455} and \frac{4845}{10455}.

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