Solve 1000+x/2*5=sqrt{3}x

$$\frac{ 1000+x }{ 2 \cdot 5 } = \sqrt{ 3 } x$$

Solve for x

$$x = \frac{10000 \sqrt{3} + 1000}{299} \approx 61.27260226$$

Steps for Solving Linear Equation

Multiply 2 and 5 to get 10.

$$\frac{1000+x}{10}=\sqrt{3}x$$

Divide each term of 1000+x by 10 to get 100+\frac{1}{10}x.

$$100+\frac{1}{10}x=\sqrt{3}x$$

Subtract \sqrt{3}x from both sides.

$$100+\frac{1}{10}x-\sqrt{3}x=0$$

Subtract 100 from both sides. Anything subtracted from zero gives its negation.

$$\frac{1}{10}x-\sqrt{3}x=-100$$

Combine all terms containing x.

$$\left(\frac{1}{10}-\sqrt{3}\right)x=-100$$

Divide both sides by \frac{1}{10}-\sqrt{3}.

$$\frac{\left(\frac{1}{10}-\sqrt{3}\right)x}{\frac{1}{10}-\sqrt{3}}=-\frac{100}{\frac{1}{10}-\sqrt{3}}$$

Dividing by \frac{1}{10}-\sqrt{3} undoes the multiplication by \frac{1}{10}-\sqrt{3}.

$$x=-\frac{100}{\frac{1}{10}-\sqrt{3}}$$

Divide -100 by \frac{1}{10}-\sqrt{3}.

$$x=\frac{10000\sqrt{3}+1000}{299}$$