Solve 10-x/3leq2x+1

$$\frac{ 10-x }{ 3 } \leq 2x+1$$

Solve for x

$$x\geq 1$$

Solution Steps

Multiply both sides of the equation by 3. Since 3 is positive, the inequality direction remains the same.

$$10-x\leq 6x+3$$

Subtract 6x from both sides.

$$10-x-6x\leq 3$$

Combine -x and -6x to get -7x.

$$10-7x\leq 3$$

Subtract 10 from both sides.

$$-7x\leq 3-10$$

Subtract 10 from 3 to get -7.

$$-7x\leq -7$$

Divide both sides by -7. Since -7 is negative, the inequality direction is changed.

$$x\geq \frac{-7}{-7}$$

Divide -7 by -7 to get 1.

$$x\geq 1$$