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-\frac{x}{4}+1>0 \frac{2x}{5}-\frac{1}{2}<0
For the quotient to be negative, -\frac{x}{4}+1 and \frac{2x}{5}-\frac{1}{2} have to be of the opposite signs. Consider the case when -\frac{x}{4}+1 is positive and \frac{2x}{5}-\frac{1}{2} is negative.
x<\frac{5}{4}
The solution satisfying both inequalities is x<\frac{5}{4}.
\frac{2x}{5}-\frac{1}{2}>0 -\frac{x}{4}+1<0
Consider the case when \frac{2x}{5}-\frac{1}{2} is positive and -\frac{x}{4}+1 is negative.
x>4
The solution satisfying both inequalities is x>4.
x<\frac{5}{4}\text{; }x>4
The final solution is the union of the obtained solutions.