Solve 1-Delta/4a=3

$$\frac{ 1- \Delta }{ 4a } = 3$$

Solve for a

$$a=\frac{1-\Delta }{12}$$

$$\Delta \neq 1$$

Steps for Solving Linear Equation

Variable a cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 4a.

$$1-\Delta =12a$$

Swap sides so that all variable terms are on the left hand side.

$$12a=1-\Delta$$

Divide both sides by 12.

$$\frac{12a}{12}=\frac{1-\Delta }{12}$$

Dividing by 12 undoes the multiplication by 12.

$$a=\frac{1-\Delta }{12}$$

Variable a cannot be equal to 0.

$$a=\frac{1-\Delta }{12}\text{, }a\neq 0$$

Solve for Δ

$$\Delta =1-12a$$

$$a\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 4a.

$$1-\Delta =12a$$

Subtract 1 from both sides.

$$-\Delta =12a-1$$

Divide both sides by -1.

$$\frac{-\Delta }{-1}=\frac{12a-1}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$\Delta =\frac{12a-1}{-1}$$

Divide 12a-1 by -1.

$$\Delta =1-12a$$