Solve 1*5+7/8+0*7777/3

$$\frac{ 1 \cdot 5+ \frac{ 7 }{ 8 } +0 \cdot 7777 }{ 3 }$$

Evaluate

$$\frac{47}{24}\approx 1.958333333$$

Solution Steps

Multiply 1 and 5 to get 5. Multiply 0 and 7777 to get 0.

$$\frac{5+\frac{7}{8}+0}{3}$$

Convert 5 to fraction \frac{40}{8}.

$$\frac{\frac{40}{8}+\frac{7}{8}+0}{3}$$

Since \frac{40}{8} and \frac{7}{8} have the same denominator, add them by adding their numerators.

$$\frac{\frac{40+7}{8}+0}{3}$$

Add 40 and 7 to get 47.

$$\frac{\frac{47}{8}+0}{3}$$

Add \frac{47}{8} and 0 to get \frac{47}{8}.

$$\frac{\frac{47}{8}}{3}$$

Express \frac{\frac{47}{8}}{3} as a single fraction.

$$\frac{47}{8\times 3}$$

Multiply 8 and 3 to get 24.

$$\frac{47}{24}$$

Factor

$$\frac{47}{2 ^ {3} \cdot 3} = 1\frac{23}{24} = 1.9583333333333333$$