Solve 1*1+i+i+i^2/2

$$\frac{ 1 \cdot 1+i+i+ { i }^{ 2 } }{ 2 }$$

Evaluate

$$i$$

Solution Steps

Multiply 1 and 1 to get 1.

$$\frac{1+i+i+i^{2}}{2}$$

Do the additions in 1+i+i.

$$\frac{i^{2}+1+2i}{2}$$

Calculate i to the power of 2 and get -1.

$$\frac{-1+1+2i}{2}$$

Do the additions in -1+1+2i.

$$\frac{2i}{2}$$

Divide 2i by 2 to get i.

$$i$$

Real Part

$$0$$

Solution Steps

Multiply 1 and 1 to get 1.

$$Re(\frac{1+i+i+i^{2}}{2})$$

Do the additions in 1+i+i.

$$Re(\frac{i^{2}+1+2i}{2})$$

Calculate i to the power of 2 and get -1.

$$Re(\frac{-1+1+2i}{2})$$

Do the additions in -1+1+2i.

$$Re(\frac{2i}{2})$$

Divide 2i by 2 to get i.

$$Re(i)$$

The real part of i is 0.

$$0$$